KetZoomer KetZoomer
  • 11-12-2021
  • Mathematics
contestada

If [tex]x^{2} + y^{2} = 6[/tex] and [tex]x + y = \sqrt{7}[/tex], then what is [tex]x-y[/tex]?

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LammettHash
LammettHash LammettHash
  • 11-12-2021

Recall that

(x + y)² = x² + 2xy + y²

Then if x + y = √7 and x² + y² = 6, we have

(√7)² = 6 + 2xy   ⇒   2xy = 1

We also have

(x - y)² = x² - 2xy + y²

so that

(x - y)² = 6 - 1   ⇒   (x - y)² = 5

which means x - y has two possible values, √5 or -√5.

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