softballgirl5643 softballgirl5643
  • 15-12-2021
  • Mathematics
contestada

The length of a rectangle is 1 yd more than twice its width, and the area of the rectangle is 66yd^2 . Find the dimensions of the rectangle.
Length:
Width:

Respuesta :

bear15141719
bear15141719 bear15141719
  • 15-12-2021

Answer:

width=5.5

Length=12

Step-by-step explanation:

L = 1+2W       [eq2; “length of the rectangle is 1 yd more than twice the width”]

(1+2W)(W)=66      [substitute eq2 for L in eq1]

W + 2W2= 66       [distribute]

2W2+ W – 66 = 0     [put all term on left side]

(2W-11)(W+6) = 0      [factor or use Quadratic Formula]

Substitute for W in either formula:

L = 1 + 2(5.5)

(i don't know if you understand this)

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