To solve this we use the
equation,
M1V1 = M2V2
where M1 is the
concentration of the stock solution, V1 is the volume of the stock solution, M2
is the concentration of the new solution and V2 is its volume.
M1 = .80 g H2SO4 / g solution (1018 g solution / L solution ) (1 mol / 98.08) = 8.30 M
8.30 (V1) = (5.0 M) (1.5 L)
V1 = 0.9036 L or 903.6 mL of the stock needed
