easy
remember associative property
a(bc)=(ab)c
so theerfor we can move dem around
also rembmer distributive property and how it can be expanded
ab+ac=a(b+c) therefor
ab+ac+ad=a(b+c+d)
(ca)d+x=bd+d(ayz)
minus (ca)d from both sides
x=db+d(ayz)-d(ca)
undistribute d
x=d(b+ayz-ca)
divide both sides by (b+ayz-ca)
[tex] \frac{x}{b+ayz-ca}=d [/tex]
[tex] d=\frac{x}{b+ayz-ca} [/tex]
