Respuesta :

ramylan00

Answer:

x=0 true

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Answer:

B) x=0

Step-by-step explanation:

[tex]f(x)=\frac{4x^2-36x}{x-9}\\ \\0=\frac{4x^2-36x}{x-9}\\ \\0=\frac{4x(x-9)}{x-9}\\ \\0=4x\\\\0=x\\\\x=0[/tex]

This is just a linear function in disguise, so there's only one solution

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