58STRAPS
58STRAPS 58STRAPS
  • 16-02-2022
  • Mathematics
contestada

csc A - sin A =

A. (cos^2A) / (sinA)
B. (1 - sinA) / (sinA)
C. (1 - sinA) / (cosA)

csc A sin A A cos2A sinA B 1 sinA sinA C 1 sinA cosA class=

Respuesta :

goddessboi goddessboi
  • 16-02-2022

Answer:

A) [tex]\frac{cos^2A}{sinA}[/tex]

Step-by-step explanation:

[tex]cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}[/tex]

Answer Link
jimrgrant1 jimrgrant1
  • 16-02-2022

Answer:

1st option

Step-by-step explanation:

Using the identities

csc x = [tex]\frac{1}{sinx}[/tex]

sin² x + cos²x = 1 ⇒ cos²x = 1 - sin²x

then

csc A - sinA

= [tex]\frac{1}{sinA}[/tex] - sinA

= [tex]\frac{1-sin^2A}{sinA}[/tex]

= [tex]\frac{cos^2A}{sinA}[/tex]

Answer Link

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