The quadratic equation y = -x^2 - 4x - 3 has a degree of 2
The vertex of the function is (-2,1)
How to graph the function?
The equation of the function is:
y = -x^2 - 4x - 3
Differentiate
y' = -2x - 4
Set to 0
-2x - 4 = 0
Solve for x
x = -2
Substitute -2 for x in y = -x^2 - 4x - 3
y = -(2)^2 - 4(-2) - 3
y = 1
The above means that the vertex of the function is (-2,1)
See attachment for the graph of the function
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