Answer:
Step-by-step explanation:
You have:
[tex](x+5)^2+(y-1)^2=16[/tex]
[tex](x+5)^2+(y-1)^2=4^2[/tex]
To find the center of the circle, you want to find the 'x' and 'y' values which make their respective term equal zero:
[tex](x+5)^2=0[/tex]
[tex](y-1)^2=0[/tex]
[tex]x=-5[/tex]
[tex]y=1[/tex]
The radius of the circle would be 4 due to the right side of the circle equation. Our circle is centered at (-5, 1) and has a radius of 4 units.
