Answer:
x ≥ 4
Step-by-step explanation:
Given:
[tex]\displaystyle \large{3x-1\geq 11}[/tex]
Add both sides by 1:
[tex]\displaystyle \large{3x-1+1\geq 11+1}\\\displaystyle \large{3x\geq 12}[/tex]
Divide both sides by 3:
[tex]\displaystyle \large{\dfrac{3x}{3} \geq \dfrac{12}{3}}\\\displaystyle \large{x\geq 4}[/tex]
Hence, the solution is x ≥ 4
