Answer:
D, [tex]\frac{7(x-4)}{6}[/tex]
Step-by-step explanation:
Basically you have to simplify the (x² - 16). Since it is the difference of 2 squares, it's simplified as (x + 4)(x - 4). Now that everything is simplified, you can start doing the multiplication.
[tex]\frac{(x+4)(x-4)}{6x} *\frac{7x}{(x+4)}[/tex], You can cancel out the (x+4)'s
[tex]\frac{(x-4)}{6x} *{7x}[/tex], There is a common factor between 7x and 6x. The common factor is x. So cancel out both "x".
You end up with this, [tex]\frac{7(x-4)}{6}[/tex]
