Answer: [tex]5\sqrt{2}[/tex]
Step-by-step explanation:
[tex]Distance\ formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }[/tex]
plugging in the values we know:
[tex]x_2 = 3,\ x_1=-4,\ y_2=7,\ y_1=6[/tex]
Therefore,
[tex]Distance=\sqrt{(3-(-4))^2+(7-6)^2}[/tex]
[tex]\rightarrow\ \sqrt{(3+4)^2+(1)^2}[/tex]
[tex]\rightarrow\ \sqrt{7^2+1}[/tex]
[tex]\rightarrow\ \sqrt{50}[/tex]
[tex]\rightarrow\ \sqrt{5\times5\times2}[/tex]
[tex]\rightarrow\ \large\boxed{5\sqrt{2}}[/tex]
