Answer:
See below
Explanation:
OK....here is help only
Horizontal components
b : 5 cos 20
a: 5 cos ( 180+75) = 5 cos ( 255)
Vertical components
b: 5 sin 20
a: 5 sin ( 255)
Can you take it from here?
Now you can add the horizontal and vertical components
then the magnitude of the resultant = sqrt (vert^2 + horiz^2)
Angle can be found by arctan (vert/horiz) (it will be in Q IV )
