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The reaction between Câ‚‚H2O, and Oâ‚‚ is represented by the balanced equation above. In an experiment, 0.30 mol of COâ‚‚ was produced from the reaction of 0.05 mol of Câ‚‚Hâ‚‚O with excess
Oâ‚‚. The reaction was repeated at the same temperature and in the same container, but this time 0.60 mol of COâ‚‚ was produced. Which of the following must be true?

Respuesta :

bharathparasad577

The initial amount of C2H2O  in the container must have been 0.10mol.

 C2H2O + 2 O2 = 2 CO2 + H2O

it can be clearly seen from the above reaction that 1 mol of C2H2O reacts to produce 2 mol of COâ‚‚ and Oâ‚‚ is given in excess that means the formation of product is decided by C2H2O only. So , here C2H2O is limiting reactant and Oâ‚‚ is excess reactant

0.05 mol of C₂H₂O forms 0.30 mol of CO₂ which is 6 times of C₂H₂O that  has been reacted.

Now for 0.60 moles of COâ‚‚ to form it should 0.6 divided by 6 mol of reactant that means

moles of C2H2O= 0.6/6 = 0.1 mol .


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