cgarciaest cgarciaest

14-02-2017
Mathematics

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Using the graph of f(x)=log2^X below, approximate the value of y in the equation 2^2y=3 y=4.01. y=.79. y=1.58. y=0.47

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selbyy19 selbyy19

14-02-2017

the answer would be y=.79

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