Answer:
(B)(4,-8)
Step-by-step explanation:
The given equation is:
[tex](x+2)^2=36[/tex]
Solving the above equation, we get
⇒[tex]x^2+4+4x=36[/tex]
⇒[tex]x^2+4x+4-36=0[/tex]
⇒[tex]x^2+8x-4x-32=0[/tex]
⇒[tex]x(x+8)-4(x+8)=0[/tex]
⇒[tex](x-4)(x+8)=0[/tex]
Thus, the solution is x=-8 and x=4.
Therefore, the solution set is (4,-8) and Option B is correct.
