arrenajauza8lou arrenajauza8lou

15-03-2017
Mathematics

contestada

Find the width and length of a rectangle with a perimeter of 108 and a width that is twice its length.

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rarrininger rarrininger

15-03-2017

Width = 2L
P = 2L +2W
108 = 2L + 2(2L)
108 = 2L + 4L
108 = 6L
108/6 = 6L /6
L = 18

Width = 2L
Width= 2(18)
Width = 36

Check
P = 2L +2W
108 = 2(18) +2(36)
108 = 36+72
108= 108

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