t1in3abaNipascaamont t1in3abaNipascaamont
  • 15-03-2017
  • Physics
contestada

What power is needed to lift a 49-kg person a vertical distance of 5.0 m in 20.0 s?

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Аноним Аноним
  • 15-03-2017
Power = W/t = mgh/t = 49*9.8*5/20 = 120.05W
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