gamerdj79
gamerdj79 gamerdj79
  • 15-03-2017
  • Mathematics
contestada

Suppose an investment of $6600 doubles in value every 8 years. How much is the investment worth after 40 years

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Aliwohaish12
Aliwohaish12 Aliwohaish12
  • 15-03-2017
40 years is 5 doublings.

6,600 x 2^5 = $211,200.
Answer Link
slicergiza slicergiza
  • 13-08-2019

Answer:

It will worth $ 211200

Step-by-step explanation:

Since, the amount formula that doubles in every t years,

[tex]A=P(2)^\frac{n}{t}[/tex]

Where, n is the total years,

Here, P = $ 6600,

n = 40 years,

t = 8

Hence, the amount after 40 years,

[tex]A=6600(2)^\frac{40}{8}[/tex]

[tex]=6600(2)^5[/tex]

[tex]=\$ 211200[/tex]

Answer Link

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