Respuesta :

the cheap answer is, well, is compounding every year, thus use the compound interest equation

[tex]\bf \qquad \textit{Compounded Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \qquad \begin{cases} A=\textit{current amount}\\ P=\textit{original amount }\to &\$1500\\ r=rate\to 2\%\to \frac{2}{100}\to &0.02\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, so once} \end{array}\to &1\\ t=years\to &4 \end{cases}[/tex]

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