If the function is: f ( x ) = 7 sin x + 1; f ( 0 ) = 7 * sin (0) + 1 = 0 + 1 = 1 f ( π/2 ) = 7 * sin (π/2) + 1 = 7 * 1 + 1 = 7 + 1 = 8 The rate of change is: ( y2 - y1 ) / ( x2- x1 ) = ( 8 - 1 ) / ( π/2 - 0 ) = = 7 / π/2 = 14 / π Answer: The rate of change on the interval from x=0 to x =π/2 is 14/π.
