-- The x-intercept is the point where the line crosses the x-axis. -- 'Y' is zero at every point on the x-axis. -- So y=0 at the x-intercept.
You say that you have the equation of the line, and it's in slope/intercept form ? Y = mx + b Great !
Just set y=0. Then you have mx + b = 0 . Solve that for 'x' , and you have the x-intercept.
(It turns out to be x = - b/m . Always true, and a very handy formula to remember if you can, and then you always have the x-intercept at your fingertips whenever you need it.)