seems to be geometric
times 2 each time
an=a1(r)^(n-1)
a1=first term
r=common ratio
n=which one
a1=1
r=2
so
sum where
a1=first term
r=common ratio
n=which one
[tex]S_n= \frac{a_1(1-r^n)}{1-r} [/tex]
to n=10
[tex]S_{10}= \frac{1(1-2^10)}{1-2} [/tex]
[tex]S_{10}= \frac{1(-1024)}{-1} [/tex]
1024 is thesum
