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15-07-2017
Mathematics

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What is the probability of getting two heads and two tails in four flips of a fair coin?

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Аноним Аноним

15-07-2017

Number of combinations possible = 4! / 2! 2! = 6

Each of these has probability 1/2*1/2*1/2*1/2 = 1/16

Required probability = 6 * 1/16 = 3/8

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