jenailee301 jenailee301
  • 15-08-2017
  • Mathematics
contestada

how to find the range of f(t)=t^2-6t

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apologiabiology
apologiabiology apologiabiology
  • 15-08-2017
the range is the highest y value to the lowest y value

ok


find the vertex because it is the highest or lowest point in the equation
make into f(t)=a(x-h)²+k form
(h,k) is the vertex
k is the y value of the vertex
if a>0, then the vertex is the minimum
if a<0, then the vertex is the maximum

so
f(t)=t²-6t
f(t)=t²-6t+9-9
f(t)=(t-3)²-9
f(t)=1(t-3)-9

k=-9
a=1
1>0
so y=-9 is the minimum value
the maximum value will be infinity

so the range is from y=-9 to infintiy
so R=[9,∞)
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