budex budex
  • 15-08-2017
  • Mathematics
contestada

find volume of cone z=sqrt(x^2+y^2) that is bounded with z=5 and z=7

Respuesta :

LammettHash
LammettHash LammettHash
  • 15-08-2017
Convert to cylindrical coordinates first, using

[tex]\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}[/tex]

Then the volume is

[tex]\displaystyle\int_{\zeta=5}^{\zeta=7}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\zeta}r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta[/tex]
[tex]=\displaystyle\pi\int_{\zeta=5}^{\zeta=7}\zeta^2\,\mathrm d\zeta[/tex]
[tex]=\dfrac{218\pi}3[/tex]
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