Respuesta :
[tex]\bf 3x^2-2+7x=0\implies
\begin{array}{llccll}
&{{ 3}}x^2&{{ +7}}x&{{ -2}}&=0\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}[/tex]
discriminant is (-2)^2 - 4*3 * 7
= 4 - 84 = -80
there are 2 roots both complex numbers
= 4 - 84 = -80
there are 2 roots both complex numbers
