jmoney1230 jmoney1230
  • 15-08-2017
  • Mathematics
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What's the concavity of f(x)=x^2+4x

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jdoe0001 jdoe0001
  • 15-08-2017
[tex]\bf f(x)=x^2+4x\qquad \cfrac{df}{dx}=2x+4\qquad \boxed{f''(x)=2}\impliedby \begin{array}{llll} \textit{just a positive}\\ constant \end{array}[/tex]

there are no inflection points, because it never changes concavity, is just a constant and thus for any region over the x-axis, will always be a positive value, and thus is always "concave up".
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