Answer:Lola ride for [tex]\frac{1}{10}[/tex] of an hour extra on Saturday as compared to Sunday
Step-by-step explanation:
Given: Lola rode her bike for [tex]\frac{7}{10}[/tex] of an hour on saturday
and for [tex]\frac{3}{5}[/tex] of an hour on sunday
Therefore difference of the two rides time
⇒[tex]\frac{7}{10}[/tex]-[tex]\frac{3}{5}[/tex]
Multiplying and dividing [tex]\frac{3}{5} by 2[/tex]
⇒[tex]\frac{7}{10} -\frac{6}{10}[/tex]
⇒[tex]\frac{1}{10}[/tex] of an hour