Answer:
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Question 1) : Â The answer is: Â " f(2) = 5 " .
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Given the quadratic function:
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  " f(x) = x² + 1 "  ;  Â
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FInd the value of: Â " f(2) " ; Â that is, when "x = 2" ; what is the resulting value?
So, replace all values of "x" in the function with "2" ; and solve to find the "output" ;
  f(2) = (2)² + 1  = (2 * 2)  +  1  =  4 + 1 = 5  .
The answer: Â f(2) = 5 .
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Question 2):
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Given:  " f(x)  =  x² − 3x² + 2 " ;  Find:  "f(3)" ;  that is, when "x = 3" ; what is the resulting value?
So;  replace all values of "x" in the function with "3" ; and solve to find the "output" ;
   f(3) = (3)² − 3(3²) + 2 ;
      = 9 − (3)(9) + 2 ;
      = 9 − 27 + 2 ;
      Â
      = (9 − 27) + 2 ;
Â
      =  - 18 + 2 ;
      =  -16 .
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The answer is: Â Â f(3) = - 16 .
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Hope these explanations ar of some help.