13-10-2017
Mathematics

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Let f(x)=square root of x-5. Find f^-1

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wizard123 wizard123

13-10-2017

Solve for 'x'

[tex]\sqrt{x-5} = y \\ \\ x - 5 = y^2 \\ \\ x = y^2 + 5[/tex]

Therefore the inverse function is:
[tex]f^{-1} (x) = x^2 +5[/tex]

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