[tex] \dfrac{ \frac{x}{4} + \frac{1}{8} }{ \frac{x^2}{4} } =
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= \dfrac{ \frac{2x}{8} + \frac{1}{8} }{\frac{x^2}{4}}
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= \dfrac{ \frac{2x+1}{8} }{\frac{x^2}{4}}
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= \dfrac{2x + 1}{8} \times \dfrac{4}{x^2}
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= \dfrac{2x + 1}{2x^2}[/tex]
