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the number of customers for a new online business can be modeled by y=10x^2+50x+300 where x represents the number of months since the business started which is the best prediction for the number of customers in month 20?

Respuesta :

deadeye8360
5300 Customers.

Work: 10(20)^2+50(20)+300

We are changing x to 20 because x represents the number of months and it asks for the amount of customers on month 20.

Answer:

5300 no. of customers

Step-by-step explanation:

Given :  [tex]y=10x^2+50x+300[/tex] model of new online business

where x represents the number of months

To find:  Best prediction for the number of customers in month 20

Solution: The model is given for x months =  [tex]y=10x^2+50x+300[/tex]

               The model is given for 20 months= [tex]y=10(20)^2+50(20)+300[/tex]

                                                                       ⇒  [tex]y=10(400)+1000+300[/tex]

                                                                      ⇒   [tex]y=10(400)+1000+300[/tex]

                                                                        ⇒  [tex]y=5300[/tex]

Therefore, 5300 no. of customers is predicted

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