Respuesta :
Formula for heightÂ
 r(t) = a/2 t² + v₀ t + r₀
 whereÂ
 a = acceleration = -32 ft/sec² (gravity)Â
 vâ‚€ = initial velocityÂ
 râ‚€ = initial heightÂ
 r(t) = -16t² + v₀ t + r₀
 Tomato passes window (height = 450 ft) after 2 seconds:Â
 r(2) = 450
 -16(4) + vâ‚€ (2) + râ‚€ = 450Â
 râ‚€ = 450 + 64 - 2vâ‚€Â
 râ‚€ = 514 - 2vâ‚€Â
 Tomato hits the ground (height = 0 ft) after 5 seconds:Â
 r(5) = 0Â
 -16(25) + v₀ (5) + r₀ = 0
 râ‚€ = 16(25) - 5vâ‚€Â
 râ‚€ = 400 - 5vâ‚€Â
Â
 r₀ = 514 - 2v₀ and r₀ = 400 - 5v₀
 514 - 2v₀ = 400 - 5v₀
 5v₀ - 2v₀ = 400 - 514
 3vâ‚€ = −114Â
 vâ‚€ = −38Â
 Initial velocity = −38 ft/sec (so tomato was thrown down)Â
 (initial height = 590 ft)Â
 r(t) = a/2 t² + v₀ t + r₀
 whereÂ
 a = acceleration = -32 ft/sec² (gravity)Â
 vâ‚€ = initial velocityÂ
 râ‚€ = initial heightÂ
 r(t) = -16t² + v₀ t + r₀
 Tomato passes window (height = 450 ft) after 2 seconds:Â
 r(2) = 450
 -16(4) + vâ‚€ (2) + râ‚€ = 450Â
 râ‚€ = 450 + 64 - 2vâ‚€Â
 râ‚€ = 514 - 2vâ‚€Â
 Tomato hits the ground (height = 0 ft) after 5 seconds:Â
 r(5) = 0Â
 -16(25) + v₀ (5) + r₀ = 0
 râ‚€ = 16(25) - 5vâ‚€Â
 râ‚€ = 400 - 5vâ‚€Â
Â
 r₀ = 514 - 2v₀ and r₀ = 400 - 5v₀
 514 - 2v₀ = 400 - 5v₀
 5v₀ - 2v₀ = 400 - 514
 3vâ‚€ = −114Â
 vâ‚€ = −38Â
 Initial velocity = −38 ft/sec (so tomato was thrown down)Â
 (initial height = 590 ft)Â
The velocity at which the tomato was thrown is -38 m/s and the direction is downwards.
The given parameters;
- height of the window, h = 450 ft
- first time to pass the window, t = 2 seconds
- time to hit the ground = 5 seconds
The height traveled by the tomato at the given time is calculated as follows;
[tex]h = h_0 + v_0t - \frac{1}{2} gt^2[/tex]
where;
- g is acceleration due to gravity = 32 ft/s²
when the time is 2 seconds;
[tex]450 = h_0 + 2v_0 \ - \ (0.5 \times 32 \times 2^2)\\\\450 = h_0 + 2v_0 - 64\\\\450 + 64 = h_0 + 2v_0\\\\514 = h_0 + 2v_0\\\\h_0 = 514 - 2v_0 \ \ ---(1)[/tex]
when the time is 5 seconds;
[tex]0 = h_0 + 5v_0 - (0.5 \times 32 \times 5^2)\\\\0 = h_0 + 5v_0 -400\\\\400 = h_0 + 5v_0[/tex]
from equation 1, the initial velocity of the ball is calculated as follows;
[tex]400 = h_0 + 5v_0\\\\ 400 = (514 - 2v_0) + 5v_0\\\\400 = 514 - 2v_0 + 5v_0\\\\400-514 = 3v_0\\\\-114 = 3v_0\\\\\v_0 = \frac{-114}{3} \\\\v_0 = -38 \ m/s[/tex]
Thus, the velocity at which the tomato was thrown is -38 m/s and the direction is downwards.
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