anai3 anai3
  • 13-02-2018
  • Mathematics
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How do you find the are of a triangle with measures of 35,35,and 12

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cdw2014
cdw2014 cdw2014
  • 13-02-2018
If we know the lengths of all three sides, we can solve for area using Heron's formula. 

First  we need to find half of the perimeter. We will call it s:

[tex]s= \frac{35+35+12}{2}=41 [/tex]

Now we know sides a, b, and c, as well as s. Now just plug they values into the following formula:

[tex]A= \sqrt{s(s-a)(s-b)(s-c)} [/tex]

[tex]A= \sqrt{41(41-35)(41-35)(41-12)} [/tex]

[tex]A= \sqrt{41(6)(6)(29)} = 206.89 [/tex]

The area is 206.89
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