1) y=0.94x+12.5 for x=40 months y=0.94*40+12.5=50.1------------------ > *1000=$50100 the answer is $50100
2) the companys sales increase per months is equal to the slope of the equation of the line y=0.94x+12.5--------------------- > y=mx+b the slope m=0.94 094*1000=940 $/month the answer is 940 $/month
3) the equation of the trend line is k=mj+b
I take two points of the graph point A(2,24) point B(10,8) m=(k2-k1)/(j2-j1)------------- >(8-24)/(10-2)=-2 m=-2 then k=mj+b--- >for point B(10,8) 8=-2*(10)+b------ > b=28 k=-2j+28 the answer is k=-2j+28
4) the line which is a model lineal for the data is the one shown in the attached figure (because that line shows the estimated values closest to the real values)
