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16-02-2018
Mathematics

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these triangles are similar so how do I solve for x?

these triangles are similar so how do I solve for x class=

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harpazo harpazo

16-02-2018

2x - 11/21 = 12/28

21 ° 12 = 28(2x - 11)

252 = 56x - 308

252 + 308 = 56x

560 = 56x

560/56 = x

10 = x

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