A jet leaves an airport traveling at a steady rate of 600 km/h. Another jet leaves the same airport 3/4 later traveling at 800 km/h in the same direction. How long will it take the second jet to overtake the first?
Let us assume the time taken by the second jet to overtake the first jet = x Let us assume the distance traveled by the second jet = d Head start that the first plane gets over the second plane (d1) = 600 * (3/4) Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 150 * 3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 450 Then We get the equation for the second jet as d = 800t the equation of the first jet comes out to be d - 450 = 600t Now let us put the value of d from the first equation we get d - 450 = 600t 800t - 450 = 600t 800t - 600t = 450 200t = 450 t = 450/200 Â = 45/20 Â = 2.25 hours So from the above deduction we can conclude that it will take 2.25 hours for the second jet to overtake the first jet.
