The volume of the cone is:
[tex]\displaystyle V= \frac{1}{3} \pi r^2 h,[/tex]
where h is for height and r is for radius. We have all we need :)
So:
[tex]\displaystyle V= \frac{1}{3} \pi 7^2 \cdot 10= \frac{1}{3} 490 \pi \approx \frac{1538.6}{3} \approx 512.86 (in^3)[/tex]
Answer is: 512.86 cubic inches
