Q4 Q23.) Solve the following exponential equation. Express the solution set in terms of natural logarithms. Then use a calculator to obtain a decimal​ approximation, correct to two decimal​ places, for the solution.
Let z = e^(2x). Then your equation is  z^2 +3z -28 = 0  (z +7)(x -4) = 0  z = -7 or 4
Taking the log of our definition of z, we have  ln(z) = 2x  x = ln(z)/2 So, the one real solution is  x = ln(4)/2 = ln(√4)  x = ln(2) The decimal approximation is  x ≈ 0.69