Given
In ΔABC
Find out the value of sin C.
To proof
As shown in diagram
∠BAC = 90°
AB = c
BC = a
CA = b
in Δ ABC
AB is perpendicular
AC is base
BC is hypotenuse
Now by trignometric function
[tex]sinC =\frac{Perpendicular}{Hypotenuse}[/tex]
[tex]sinC = \frac{AB}{BC}[/tex]
put all the value mentioned above
[tex]sinC =\frac{c}{a}[/tex]
Thus the correct option is second.
Hence proved
